question_answer

A garden is 90 m long and 75 m broad. A path 5 m wide is to be build outside and around it. Find the area of the path. Also find the area of the garden in hectare.

Answer:

Let ABCD be the garden, and let PQRS be the external boundaries of the path. We have,           AB = 90 m AD = 75 m PQ = (90 + 5 + 5) m                                                                                                      =100 m and  QR - (75 + 5 + 5) = 85 in Now, Area of the path = Area of PQRS                                                                                                     -Area of ABCD \[=\left( 100\times 85-90\times 75 \right){{m}^{2}}\] \[=\left( 8500-6750 \right){{m}^{2}}\] \[=1750{{m}^{2}}\] Area of the garden = Area of ABCD \[=\left( 90\times 75 \right){{m}^{2}}-6750{{m}^{2}}\] \[=\frac{6750}{10000}\]hectare = 0.675