Answer:
Let the equal angles be x \[x+x+110{}^\circ =180{}^\circ \](By angle sum property) \[2x\text{ }+\text{ }110{}^\circ \text{ }-\text{ }180{}^\circ \] \[2x-180{}^\circ -110{}^\circ \] \[2x-70{}^\circ \] \[x=\frac{{{70}^{\circ }}}{2}\] x = \[35{}^\circ \] Hence, equal angles are of\[35{}^\circ \].
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