Answer:
Let ABC be the given triangle such that \[AB=12\text{ }cm,BC=14\text{ }cm\] So, perimeter \[=AB+BC+CA\] \[=36\text{ }cm\] \[12cm+14\text{ }cm+CA=36\text{ }cm\] \[CA=36\text{ }cm26\text{ }cm=10\text{ }cm\] \[\therefore \] The third side is 10 cm.
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