6th Class Mathematics Sample Paper Mathematics Sample Paper-6

  • question_answer
    Determine if the following are in proportion:
    (a) 15, 45, 40, 120     
    (b) 33, 121, 9, 96
    (c) 24, 28, 36, 48        
    (d) 32, 48, 70,210
    (e) 4, 6, 8, 12              
    (f) 33, 44, 75,100

    Answer:

    (a) We have, \[15:45=\frac{15}{45}=\frac{1}{3}\]
    and                   \[40:120=\frac{40}{120}=\frac{1}{3}\]
    Since,                \[15:45=40:120\]
    So, 15, 45, 40, 120 are in proportion. Other method: We have,
    Product of extremes \[=15\times 120=1800\]
    Product of middle terms \[=45\times 40=1800\]
    Product of extremes = Product of middle terms Hence, 15, 45, 40, 120 are in proportion.
    (b) We have \[33:121=\frac{33}{121}=\frac{3}{11}\]
    and                      \[9:96=\frac{9}{96}=\frac{3}{32}\]
    Therefore,   \[\frac{3}{11}\ne \frac{3}{32}\]
    So,            \[~33:121\ne 9:96\]
    Thus, 33, 121, 9, 96 are not in proportion. Other method: We have,
    Product of extremes \[=33\times 96=3168\]
    Product of middle terms \[=121\times 9=1089\]
    Product of extremes \[\ne \] Product of middle terms
    Hence, 33, 121, 9, 96 are not in proportion.
    (c) We have, \[~24:28=\frac{24}{28}=\frac{6}{7}\]
    and                    \[36:48=\frac{36}{48}=\frac{3}{4}\]
    Since,                \[\frac{6}{7}\ne \frac{3}{4}\]
    Therefore,   \[24:28\ne 36:48\]
    They, 24, 28, 36, 48 are not in proportion.
    (d) We have,     \[32:48=\frac{32}{48}=\frac{2}{3}\]
    and                      \[70:210=\frac{70}{210}\text{=}\frac{1}{3}\text{ }\]
    Since,                \[\frac{2}{3}\ne \frac{1}{3}\]
    Therefore,   \[32:48\ne 70:210\]
    Hence, 32, 48, 70, 210 are not in proportion.
    (e) We have,      \[4:6=\frac{4}{6}=\frac{2}{3}\]
    and                   \[8:12=\frac{8}{12}=\frac{2}{3}\]
    So,                   \[4:6=8:12\]
    Therefore, 4, 6, 8, 12 are in proportion.
    Other method : We have
    Product of extremes \[=4\times 12=48\]
    Product of middle terms \[=6\times 8=48\]
    Product of extremes = product of middle terms Hence, 4, 6, 8, 12 are in proportion.
    (f) We have,      \[33:44=\frac{33}{44}=\frac{3}{4}\]
    and                   \[75:100=\frac{75}{100}=\frac{3}{4}\]
    So,                   \[33:44=75:100\]
    Therefore, 33, 44, 75, 100 are in proportion.


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