question_answer

Solve the following equations:

(a) 4 = 5 (p - 2)

(b) -4 = 5 (p - 2)

(c) -16 = -5 (2 - p)

Answer:

(a) We have,

4 = 5(p ? 2)

4 = 5p ? 10

[Expanding the bracket on RHS]

5p = ? 10 ? 4

[Transposing 4 on RHS and 5p on LHS]

\[-5p=14\]

\[\frac{-5p}{-5}=\frac{14}{-5}\]

[Dividing both sides by ? 5]

\[p\text{ }=\frac{14}{5}\]

(b) We have, ? 4 = 5(p ? 2)

-4 = 5p ? 10

[Expanding the bracket on RHS]

-5p = ? 10 + 4

[Transposing ? 4 on RHS and 5p on LHS]

-5p = ? 6

\[\frac{-5p}{-5}=\frac{6}{-5}\]

[Dividing both sides by ? 5]

p = \[\frac{6}{5}\]

(c)  ? 16 = ? 5 (2 ? p)

?16 = ? 10 + 5p

?6 = 5p

or         p = \[\frac{-6}{5}\]