Solve for y: |
(a) \[2y+\frac{5}{2}=\frac{37}{2}\] |
(b) \[\frac{y}{5}+3=2\] |
Answer:
(a) \[2y+\frac{5}{2}=\frac{37}{2}\] \[2y=\frac{37}{2}--\frac{5}{2}\] \[2y=\frac{37-5}{2}\] \[2y=\frac{32}{2}\] 2y = 16 \[\frac{2y}{2}=\frac{16}{2}\] [Dividing by 2] Thus, y = 8 (b) \[\frac{y}{5}+3=2\] \[\frac{y}{5}=2-3\] \[\frac{y}{5}=-1\] \[\frac{y}{5}=-1\times 5\] \[\frac{y}{5}=-5\]
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