Answer:
Let the numbers be 2x, 3x and 5x \[\therefore \,\,\,{{\left( 2x \right)}^{2}}+{{\left( 3x \right)}^{2}}+{{\left( 5x \right)}^{2}}=608\] \[4{{x}^{2}}+9{{x}^{2}}+25{{x}^{2}}=608\] \[38\text{ }{{x}^{2}}=608\] \[{{x}^{2}}=\frac{608}{38}=16\] x = 4 So, the number are 8, 12 and 20.
You need to login to perform this action.
You will be redirected in
3 sec