Solve the following equations: |
(a) 4 = 5 (p - 2) |
(b) -4 = 5 (p - 2) |
(c) -16 = -5 (2 - p) |
Answer:
(a) We have, 4 = 5(p ? 2) 4 = 5p ? 10 [Expanding the bracket on RHS] 5p = ? 10 ? 4 [Transposing 4 on RHS and 5p on LHS] \[-5p=14\] \[\frac{-5p}{-5}=\frac{14}{-5}\] [Dividing both sides by ? 5] \[p\text{ }=\frac{14}{5}\] (b) We have, ? 4 = 5(p ? 2) -4 = 5p ? 10 [Expanding the bracket on RHS] -5p = ? 10 + 4 [Transposing ? 4 on RHS and 5p on LHS] -5p = ? 6 \[\frac{-5p}{-5}=\frac{6}{-5}\] [Dividing both sides by ? 5] p = \[\frac{6}{5}\] (c) ? 16 = ? 5 (2 ? p) ?16 = ? 10 + 5p ?6 = 5p or p = \[\frac{-6}{5}\]
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