Answer:
Let the distance travelled by a taxi = x km, then
Fare (in Rupees) 260 279.50 Distance (in km) 200 x
Clearly, the taxi will travel more for more money, then by direct variation. \[\frac{260}{279.50}=\frac{200}{x}\] \[\Rightarrow \] \[x=\frac{200\times 279.50}{260}\] \[\Rightarrow \] \[x=215\] Hence, the taxi will travel, \[3x\left( 4x5 \right)+3=215\]km
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