question_answer

Solve the following riddles, you may yourself construct such riddles Who am I?

(i) Go round a square

Counting every corner

Thrice and no more!

Add the count to me

To get exactly thirty four!

(ii) For each day of the week

Make an up count from me

If you make no mistake

You will get twenty three!

(iii) I am a special number

Take away from me a six!

A whole cricket team

You will still be able to fix!

(iv) Tell me who I am

I shall give a pretty clue!

You will get me back

If you take me out of twenty two!

Answer:

(i) Let I be denoted by x. There are 4 corners of a square.

On counting each corner thrice, we get \[3\times 4=12\]

According to the question,

\[x+12=34\]

\[\Rightarrow \]   \[x+1212=3412\]

\[x+0=22\]

\[\Rightarrow \]   \[x=22\]

Hence, I am 22.

(ii) According to the question.

\[x+7=23\]

\[\Rightarrow \]   \[x+77=237\]

\[\Rightarrow \]   \[x+0=16\]

\[x=16\]

(iii) Let the special number be x. Then according to the question

[In cricket team, no. of players be 11]

\[x6=11\]

\[\Rightarrow \]   \[x6+6=11+6\]

\[\Rightarrow \]   \[x+0=17\]

\[\Rightarrow \]   \[x=17\]

Hence, the special number is 17.

(iv) Let I be denoted by x. Then according to the question.

\[22x=x\]

\[\Rightarrow \]   \[22x+x=x+x\]

\[\Rightarrow \]   \[22+0=2x\]

\[\Rightarrow \]   \[2x=22\]

\[\Rightarrow \]   \[x=11\]

Thus, I am 11.