Answer:
Sides of a trapezium are BC = 48 m, CD = 17 m and AD = 40 m, AB =? Length of the fence of a trapezium shaped = 120 m Perimeter of trapezium = Length of fence of trapezium ABCD shaped \[AB\text{ }+\text{ }BC\text{ }+\text{ }CD\text{ }+\text{ }AD\text{ }=\text{ }120\] \[AB\text{ }+\text{ }48\text{ }+\text{ }17\text{ }+\text{ }40\text{ }=\text{ }120\] \[AB\text{ }+\text{ }105\text{ }=\text{ }120\] \[AB\text{ }=\text{ }120\text{ }\text{ }105\] \[AB\text{ }=\text{ }15\text{ }m.\] Two parallel sides of trapezium, AD = 40 m, BC = 48 m. Perpendicular height between them, AB = 15 m Then, the area of trapezium field \[=\frac{1}{2}\times h\times \] (sum of parallel sides) \[=\frac{1}{2}\times 15\times (40+48)\] \[=\frac{1}{2}\times 15\times 88\] \[=\text{ }660\text{ }{{m}^{2.}}\]
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