Answer:
In \[\Delta LOM,\text{ }\angle OLM+\angle OML+\angle LOM=180{}^\circ \] \[70{}^\circ +20{}^\circ +\angle LOM=180{}^\circ \] \[90{}^\circ +\angle LOM=180{}^\circ \] \[\angle LOM=180{}^\circ -90{}^\circ =90{}^\circ \] \[\angle LOM=\angle PON\] [since, vertically opposite angles are equal] \[\angle PON=90{}^\circ \] In\[\Delta PON\], \[\angle PON-\angle NPO+\angle ONP=180{}^\circ \] \[90{}^\circ +\angle NPO+70{}^\circ =180{}^\circ \] \[\angle NPO=180{}^\circ -160{}^\circ =20{}^\circ \]
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