Factorise: |
(a) \[12x+36\] |
(b) \[22y-33z\] |
Answer:
(a) We have, \[12x=\text{ }3\times 2\times 2\times x~\] \[=\left( 2\times 2\times 3 \right)\times \text{ }x\] \[36=2\times 2\times 3\times 3\] \[=\left( 2\times 2\times 3 \right)\times 3~\] \[\therefore \]\[12x+36=\left[ \left( 2\times 2\times 3 \right)\times \text{ }x \right]+\left[ \left( 2\times 2\times 3 \right)\times 3 \right]\] \[=\text{ }2\times 2\times 3\left[ x+3 \right]\] \[=\text{ }12\left( x+3 \right)~\] (b) We have \[22y=\text{ }2\times 11\times y\] \[332=3\times 11\times 2\] \[22y+33z=2\times 11\times y+3\times 11\times 2\] \[=11\left( 2y+3z \right)\]
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