Answer:
Given, side of square = 5 cm \[\therefore \] Area of square \[=side\times side\] \[=5\times 5\] \[=25\text{ }sq\text{ }cm\] Now according to question, New side \[=2\times \]initial side \[=2\times 5\] \[=10\text{ }cm\] \[\therefore \] Area of new square \[=side\times side\] \[=10\times 10\] \[=100\text{ }sq\text{ }cm\]. \[\therefore \] \[\frac{\text{Area}\,\,\text{of}\,\,\text{new}\,\,\text{square}}{\text{Area}\,\,\text{of}\,\,\text{old}\,\,\text{square}}=\frac{100}{25}=4\] Hence, the area of new square is 4 times increase.
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