question_answer

When a = 0, b = -1, find the value of the given expressions:

(a) 2a+2b

(b) \[2{{a}^{2}}+\text{ }b2\text{ }+\text{ }1\]

(c) \[2{{a}^{2}}b+2a{{b}^{2}}+ab\]

Answer:

When a = 0, b = -1 then,

(a) 2a + 2b - 0 + 2(-1) = - 2

(b) \[2{{a}^{2}}+{{b}^{2}}+1-0+{{\left( -1 \right)}^{2}}+1=1+1=2\]

(c)\[2{{a}^{2}}b+2a{{b}^{2}}+ab=0+0+0=0\]