Find: |
(a) \[5\times 2\frac{3}{7}\] |
(b) \[1\frac{4}{9}\times 6\] |
Answer:
(a) \[5\times 2\frac{3}{7}=5\times \frac{2\times 7+3}{7}\] =\[5\times \frac{14+3}{7}\] =\[5\times \frac{17}{7}=\frac{5\times 17}{7}\] =\[\frac{85}{7}=12\frac{1}{7}\] (b) \[1\frac{4}{9}\times 6=\frac{1\times 9+4}{9}\times 6\] \[=\frac{9+4}{9}\times 6\] =\[\frac{13}{9}\times 6=\frac{13\times 6}{9}\] \[=\frac{78}{9}\] Dividing the numerator and denominator by 3, we get \[\frac{26}{3}=8\frac{2}{3}\]
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