6th Class Mathematics Sample Paper Mathematics Sample Paper-7

  • question_answer
    A magazine charges Rs. 300 per 10 sq cm area for advertisement. A company decided to order a half page advertisement. If each page of the magazine is \[15\text{ }cm\times 24\text{ }cm\], what amount will the company has to pay for it?

    Answer:

    Firstly, find the area of full page by using length \[\times \] breadth. Also, find area of half page and to get required cost, we multiply the area of half page by rate of advertising i.e., \[Rs.\frac{300}{10}\]                                                                       [\[\because \] rate = Rs. 300 per 10 sq. m] Given, length of each page of the magazine = 24 cm and breadth of each page of the magazine = 15 cm \[\therefore \] Area of the full page of the magazine \[=Length\times Breadth\] \[=24\text{ }cm\times 15\text{ }cm\] \[=360\text{ }sq\text{ }cm\]                                                                                                                   \[\because \] Company decided to order the half page of advertisement. \[\therefore \] Area of half page of the magazine \[=\frac{360}{2}\]                                     \[=180\,sq\,\,cm\]                                                                                                           Given, cost of per 10 sq. m = Rs. 300 Cost of 1 sq. m \[=Rs.\frac{300}{10}\] Cost of 180 sq. m \[=\frac{300}{10}\times 180\]                         \[=300\times 18\]                         \[=Rs.\,\,5400\]                                                                                                              Hence, the company will pay Rs. 5400 for it.


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