Find |
(a) \[\frac{-3}{7}+\frac{2}{3}\] |
(b) \[\frac{-5}{6}+\frac{-3}{11}\] |
Answer:
(a) Given, \[\frac{-3}{7}+\frac{2}{3}\] \[\because \]LCM of 7 and 3 = 21 So,\[\frac{-3}{7}=\frac{-3\times 3}{7\times 3}=\frac{-9}{21}\,\,and\,\,\frac{2}{3}=\frac{2\times 7}{3\times 7}=\frac{14}{21}\] \[\therefore \]\[\frac{-3}{7}+\frac{2}{3}=\frac{-9}{21}+\frac{14}{21}=\frac{-9+14}{21}=\frac{5}{21}\] (b) Given, \[\frac{-5}{6}+\frac{-3}{11}\] \[\because \] LCM of 6 and 11 = 66 \[\therefore \]\[\frac{-5}{6}=\frac{-25\times 11}{6\times 11}=\frac{-55}{66}\,\,and\,\,\frac{-3}{11}=\frac{-3\times 6}{6\times 11}=\frac{-18}{66}\] Now,\[\frac{-5}{6}+\frac{-3}{11}=\frac{-55}{66}+\frac{-18}{66}=\frac{-55(-18)}{66}\] \[=\frac{-55-18}{66}=\frac{-73}{66}\]
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