Answer:
Steps of Construction: (a) Draw AC = 5 - 5 cm. (b) At A, construct\[\angle CAX=45{}^\circ \]. (c) At C, construct\[\angle ACY=45{}^\circ \], such that \[\overline{CY}\]meets \[\overline{AX}\]at B. Then, ABC is the required isosceles triangle, in which AB = CB and\[\angle B=90{}^\circ \].
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