Sr. No | Length of Rectangle | Breadth of Rectangle | Perimeter By adding all the sides | Perimeter by 2 \[\mathbf{\times }\] (length \[\mathbf{\times }\] breadth) |
(i) | 25 cm | 12 cm | \[25\,\,cm+12\text{ }cm+\]\[25\text{ }cm+12\text{ }cm\] \[=74\text{ }cm\] | \[=2\times (25\,\,cm\]\[+12\,\,cm)\] \[=2\times (37\,\,cm)\] \[=74cm\] |
(ii) | 0.5 m | 0.25 m | ||
(iii) | 18 cm | 15 cm | ||
(iv) | 10.5 cm | 8.5 cm |
Answer:
Sr. No Length of Rectangles Breadth of Rectangle Perimeter by adding all the sides Perimeter by 2 \[\times \] (length \[\times \] breadth) (i) 0.5 cm 0.25 m = 0.5 m + 0.25 m + 0.5 m + 0.25 m = 1.50 m = 2 \[\times \] (0.5 m + 0.25 m) = 2 \[\times \] (0.75 m) = 1.50 m (ii) 18 cm 15 cm = 18 cm + 15 cm + 18 cm + 15 cm = 66 cm = 2 \[\times \] (18 cm + 15 cm) = 2 \[\times \] (33 cm) = 66 cm (iii) 10.5 cm 8.5 cm = 10.5 cm + 8.5 cm + 10.5 cm + 8.5 cm = 38 cm = 2 \[\times \] (10.5 cm + 8.5 cm) = 2 \[\times \] (19 cm) = 38 cm From above example, it is clear the perimeter of a rectangle = 2 \[\times \] (length + breadth)
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