Answer:
Here, l = 7 m, b = 6 m, h = 15 m Volume of cuboid =\[l\times b\times h\] \[=7\times 6\times 15\] \[=\text{ }630\text{ }{{m}^{3~}}\] Since, \[1\text{ }{{m}^{3}}=1000\text{ }L\] \[\therefore \] Capacity of water in reservoir \[=\text{ }630\times 1000\] = 630000 L Since, 8400 L water 5 pumped our \[\therefore \] Water left in reservoir \[=\text{ }630000-8400\] = 621600 L \[=\text{ }621.6\text{ }{{m}^{3}}~\] \[Water\text{ }level\text{ }=\frac{Volume}{Base\,Area}\] \[=\frac{624.6}{7\times 6}\] = 14.8 m Fall in water level \[=\text{ }15\text{ }-14.8\] = 0.2 m or 20 cm
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