Answer:
Here, firstly draw an angle of measure \[90{}^\circ \] ad then construct its bisector. For this, we use the following steps: Step I: Draw \[\overline{AB}\] of any length. Place the centre of the protractor at A and the zero edge along \[\overline{AB}\] Step II: Start with zero near B. Mark point C at\[90{}^\circ \]. Step III: Join AC. Then, \[\angle BAC\]is an angle of measure \[90{}^\circ \]. Step IV: Now with A as centre, draw an arc that cuts both rays of \[\angle A\]at part. Step V: With P as centre and using compasses, draw an arc whose radius is more than half of the length of PQ. Step VI: With the same radius and with Q as centre, draw another arc in the interior of ∠A. which intersects the previous arc at D. Join \[\overline{AD}\]Then, \[\overline{AD}\] is the required bisector of\[\angle A\].
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