Answer:
Length of rectangle \[=20-\left( 3.5+3.5 \right)\] \[=20-7=13m\] Breadth of rectangle = 7 m The area of rectangular \[=l\times b=13\times 7=91\,{{m}^{2}}\] The perimeter of rectangular part \[=2\left( \text{l}\,\text{+}b \right)\] \[=2\left( 13+7 \right)=40m~\] Now, radius of each semicircle = 3.5 m The area of both semicircular part \[=\pi {{r}^{2}}\] =\[=\frac{22}{7}\times 3.5\times 3.5\] = 38.5m2 The perimeter of both semicircular \[=2\pi r\] \[=2\times \frac{22}{7}\times 3.5=22m\] \[\therefore \]The area of whole garden=The area of rectangular part + The area of semi-circular part \[=91{{m}^{2}}+38.5{{m}^{2}}\] \[=\text{ }129.5{{m}^{2~}}\] The perimeter of whole garden = The perimeter of rectangular part + The perimeter of semi-circular part = 40 m + 22 m = 62 m.
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