Answer:
According to condition, Perimeter of square field = Perimeter of rectangular field \[\Rightarrow \] \[4\times side=2\left( l+b \right)\] \[\Rightarrow \] \[4\times 60=2\left( 80+b \right)\] \[\Rightarrow \] \[\frac{240}{2}=80+b\] \[\Rightarrow \] \[120-80\text{ }=b\] \[\Rightarrow \] 40 =b \[\therefore \]Breadth of rectangular field b = 40 m. Area of square field = (side)2 \[={{\left( 60 \right)}^{2}}=\text{ }3600\,{{m}^{2}}\] Area of rectangular field \[=\text{ }I\times b\] \[=\text{ }80\times 40=3200\text{ }{{m}^{2}}\] \[\therefore \] Square field has larger area.
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