Answer:
Area enclosed the copper wire In square shape \[={{\left( side \right)}^{2}}\] ∴ \[{{\left( side \right)}^{2}}=121\text{ }c{{m}^{2}}\] side\[=\sqrt{121}=11\text{ }cm\]. Hence length of wire = 11 × 4 = 44 cm New length = Circumference of the circle 2πr = 44 \[2\times \frac{22}{7}\times r=44\] \[r=\frac{44}{2\times 22}\times 7\] Thus, r = 7 cm Hence, area enclosed by the wire when it is bent in circular shape \[=\pi {{r}^{2}}\] \[=\frac{22}{7}\times {{\left( 7 \right)}^{2}}\] \[=\frac{22}{7}\times 7\times 7\] \[=\text{ }154\text{ }{{m}^{2}}.\]
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