Answer:
Let the breadth of the pool be x m Then the length of the pool = (2x + 2) m \[2(2x+2+x)=154\] or, \[\frac{2(2x+2+x)}{2}=\frac{154}{2}\] [Dividing both sides by 2] or, 3x + 2 = 77 or, \[3x+2-2=77-2\] [Subtracting 2 from both sides] or, 3x=75 or, \[\frac{3x}{3}=\frac{75}{3}\] [Dividing both sides by 3] or, x = 25 m Length of the pool \[=2x+2=2\times 25+2=50+2=52m.\] Hence, the length and the breadth of the pool is 52 m and 25 m, respectively.
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