Answer:
Let number be x Its supplement \[=180{}^\circ -x\] \[x\text{ }=\text{ }2\left( 180{}^\circ -x \right)\] \[\therefore \] \[x\text{ }=\text{ }360{}^\circ -2x\] \[3x=360{}^\circ \] \[x=120{}^\circ \]
You need to login to perform this action.
You will be redirected in
3 sec
