In the figure, AB = AC and D is the mid-point of\[\overline{BC}\]. |
(a) State the three pairs of equal parts in \[\Delta \]ADB and \[\Delta \]ADC |
(b) Is\[\Delta ADB\cong \Delta ADC\]? Give reasons. |
(c) Is \[\angle B=\angle C?\]Why? |
Answer:
(a) Three pairs of equal parts in \[\Delta ADB\]and\[\Delta ADC\] are AD = AD [Common] AB = AC [Given] and DB = DC \[\left[ \because D\text{ }is\text{ }mid-point\text{ }of\text{ }\overline{BC} \right]\] (b) By SSS criterion of congruence, \[\Delta ADB\cong \Delta ADC\] (c) Yes, \[\angle \]B = \[\angle \]C [\[\because \] Corresponding parts of congruent triangles are equal]
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