Solve the following equations: |
(a) \[2y+\frac{5}{2}=\frac{37}{2}\] |
(b) 5t + 28 = 10 |
(C) \[\frac{a}{5}+3=2\] |
(d) \[\frac{q}{4}+7=5\] |
Answer:
(a) \[2y+\frac{5}{2}=\frac{37}{2}\] \[2y=\frac{37}{2}-\frac{5}{2}\] \[2y=\frac{32}{2}\] 2y = 16 \[y=\frac{16}{2}\] \[\therefore \] y = 8 (b) 5t + 28 = 10 5t = 10 - 28 5t = -18 \[\therefore \] \[t=-\frac{18}{5}\] (c) \[~\frac{a}{5}+3=2\] \[~\frac{a}{5}=2-3\] \[~\frac{a}{5}=-1\] \[a=-1\times 5\] \[\therefore \] A = - 5 (d) \[\frac{q}{4}+7=5\] \[\frac{q}{4}=5-7\] \[\frac{q}{4}=-2\] \[q=-2\times 4\] \[\therefore \] \[q=-8\]
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