question_answer

Daniel is painting the walls & wiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m2 of area is painted. How many cans of paint will she need to paint the room?

Answer:

l = 15, m, b = 10 m and h = 7m

Total surface area of room = 2 (lb + bh + hl)

\[=2\left( 15\times 10+10\times 7+7\times 15 \right)\]

\[=2\left( 150+70+105 \right)\]

\[=650\text{ }{{m}^{2}}\]

Area of floor \[=\text{ }l\times b\]

\[=15\times 10=150\text{ }{{m}^{2}}\]

Area painted by Daniel \[=650150\]

\[=\text{ }500\text{ }{{m}^{2}}\]

\[\therefore \,\,\,\,100\text{ }{{m}^{2}}\]area painted by 1 can

\[\therefore \,\] 500 \[{{m}^{2}}\] area painted \[=\frac{1}{100}\times 500\]

= 5 cans.