Answer:
Volume of a brick = 22 cm \[\times \] 10 cm \[\times \] 7 cm \[=\text{ }1540\text{ }c{{m}^{3}}\] Dimensions of wall l = 11 m, b = 3.5 m, h = 40 cm = 0.4 m Volume of wall \[=11\times 3.5\times 0.4\] \[=\text{ }15.4\text{ }{{m}^{3}}\] \[=\text{ }15.4\times 1000000\text{ }c{{m}^{3}}\] \[=\text{ }15400000\text{ }c{{m}^{3}}\] Since, cement and sand occupy \[{{\left( \frac{1}{10} \right)}^{th}}\] part of the wall So, new volume \[=\text{ }15400000\text{ }\times \frac{1}{10}\] \[=\text{ }1540000\text{ }c{{m}^{3}}\] \[No.\text{ }of\text{ }bricks\text{ }=\frac{1540000}{1540}\] = 1000
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