question_answer

Fill in the missing fractions:

(a) \[\frac{7}{10}-=\frac{3}{10}\]

(b) \[-\frac{3}{21}=\frac{5}{21}\]

(c) \[-\frac{3}{6}=\frac{3}{6}\]

(d) \[+\frac{5}{27}=\frac{12}{27}\]

Answer:

(a) Here, \[\frac{7}{10}-=\frac{3}{10}\]

Subtracting \[\frac{7}{10}\] from both sides, we get

\[\frac{7}{10}-=\frac{3}{10}=\frac{7}{10}-\frac{3}{10}\]

Or         \[\frac{7}{10}-\frac{3}{10}-=\frac{7-3}{10}=\frac{4}{10}\]

\[\therefore \]      \[\frac{7}{10}-\frac{4}{10}=\frac{3}{10}\]

(b)        \[-\frac{3}{21}=\frac{5}{21}\]

Or         \[=\frac{5}{21}+\frac{3}{21}\]

Or         \[=\frac{5+3}{21}\]

Or         \[=\frac{8}{21}\]

\[\therefore \]      \[\frac{8}{21}-\frac{3}{21}=\frac{5}{21}\]

(c)        \[-\frac{3}{6}=\frac{3}{6}\]

\[=\frac{3}{6}+\frac{3}{6}\]

\[=\frac{3+3}{6}\]

\[=\frac{6}{6}(=1)\]

\[\therefore \]    \[1-\frac{3}{6}=\frac{3}{6}\]

(d)        \[+\frac{5}{27}=\frac{12}{27}\]

or         \[=\frac{12}{27}-\frac{5}{27}\]

or         \[=\frac{7}{27}\]

\[\therefore \]      \[\frac{7}{27}+\frac{5}{27}=\frac{12}{27}\].