Answer:
Let number be x Its supplement \[=180{}^\circ -x\] \[x\text{ }=\text{ }2\left( 180{}^\circ -x \right)\] \[\therefore \] \[x\text{ }=\text{ }360{}^\circ -2x\] \[3x=360{}^\circ \] \[x=120{}^\circ \]
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