Answer:
Given, \[\Delta PQR\]is right angled at P, in which PQ = 10 cm and PR = 24 cm In,\[\Delta PQR\] by using Pythagoras theorem, \[Q{{R}^{2}}=P{{Q}^{2}}+P{{R}^{2}}\Rightarrow Q{{R}^{2}}={{\left( 10 \right)}^{2}}+{{\left( 24 \right)}^{2}}\] \[Q{{R}^{2}}=100+576\Rightarrow Q{{R}^{2}}=676\] \[QR=\sqrt{676}=26\] Hence, the length of QR is 26 cm.
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