Answer:
Juhi sells a machine for Rs 13,500 She loses in bargain =20% The price she bought it be x. As here/ S.P - ?13/500 Loss % = 20% \[\therefore \] CP =? Loss = C.E - S.E Loss = x - 13,500 ... (1) Here, Loss % = 20% \[\because \]Loss% =\[\frac{Loss}{C.P}\times 100\] \[\therefore \] 20 =\[\frac{Loss}{X}\times 100\] \[\frac{20x}{100}=Loss\] ... (2) Placing value of (2) in (1), We get \[\frac{20x}{100}=[x-13,500]\] 20x = (x- 13500)100 20x = 100x-1350000 13, 50, 000 = (100 - 20)x 13, 50, 000 = 8x x =\[\frac{13,50,000}{80}\] x= Rs 16,875.
You need to login to perform this action.
You will be redirected in
3 sec