Answer:
Let ABCD be a parallelogram such that adjacent angles are equal. \[\angle A\text{ }=\angle B\] Since, \[\angle A+\angle B=180{}^\circ \] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,2\angle A=180{}^\circ \] \[\therefore \,\,\,\,\,\,\,\,\angle A\text{ }=\angle B=\frac{180{}^\circ }{2}=90{}^\circ \] Since, opposite angles of a parallelogram are equal. \[\therefore \,\,\,\,\,\,\,\,\,\angle A=\angle C=90{}^\circ \,\] and \[\angle B=\angle D=90{}^\circ \] Thus, \[\angle A=\text{ }90{}^\circ ,\angle B=90{}^\circ ,\] \[\angle C=90{}^\circ \]and\[\angle D=90{}^\circ ~\]
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