(a) Subtract \[4a\text{ }-\text{ }7ab\text{ }+\text{ }3b\text{ }+\text{ }12\]from |
\[12a\text{ }-\text{ }9ab\text{ }+\text{ }5b\text{ }-\text{ }3\] |
(b) Subtract \[3xy+\text{ }5yz-7zx\]from |
\[5xy-\text{ }2yz-2zx+10xyz\] |
(c) Subtract \[4{{p}^{2}}q-3pq+5p{{q}^{2}}-8p+7q-10\] |
From \[18-3p-11q+5pq-2p{{q}^{2}}+5{{p}^{2}}q\] |
Answer:
(a) \[12a9ab+5b3\] \[4a7ab+3b+12\] \[\frac{\left( \right)\text{ }\left( + \right)\text{ }\left( \right)\text{ }\left( \right)\text{ }subtracting}{8a\text{ }\text{ }2ab\text{ }+\text{ }2b\text{ }\text{ }15}\] (b)\[5xy\text{ }\text{ }2yz\text{ }\text{ }2zx\text{ }+\text{ }10xyz\] \[3xy\text{ }+\text{ }5yz\text{ }\text{ }7zx\] \[\frac{\left( \right)\text{ }\left( \right)\text{ }\left( + \right)\text{ }subtracting}{2xy\text{ }\text{ }7yz\text{ }+\text{ }5zx\text{ }+\text{ }10xyz}\] (c) \[183p11q+5pq2p{{q}^{2}}+5{{p}^{2}}q\] \[-108p+7q3pq+5p{{q}^{2}}+4{{p}^{2}}q\] \[\frac{\left( + \right)\text{ }\left( + \right)\text{ }\left( \right)\text{ }\left( + \right)\text{ }\left( \right)\,\,\text{ }\left( \right)}{28+5p18q+8pq7p{{q}^{2}}+{{p}^{2}}q}\] Therefore, \[{{p}^{2}}q7p{{q}^{2}}+8pq18q+5p+28\]
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