A) \[\frac{1}{1+\sin \,x}\]
B) \[\frac{-1}{1+\sin \,x}\]
C) \[\frac{1}{{{(1+\sin \,x)}^{2}}}\]
D) \[\frac{-1}{{{(1+\sin \,x)}^{2}}}\]
E) None of these
Correct Answer: B
Solution :
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