A) \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=2\]
B) \[{{y}^{2}}+2\,\sqrt{y}-3=0\]
C) \[3{{y}^{2}}-4y+2=2{{y}^{2}}-2y-4\]
D) \[x+\frac{1}{x}=4{{x}^{8}}\]
E) None of these
Correct Answer: C
Solution :
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