A) 3 : 4
B) 4 : 5
C) 2 : 3
D) 1 : 2
Correct Answer: D
Solution :
[d] Let ABCD is a square whose side is ?a? units. DB is its diagonal and DBQP is square drawn in diagonal DB of square ABCD Area of ABCD \[=a\times a={{a}^{2}}\] ? (1) From \[\Delta ABD\] \[D{{B}^{2}}=A{{B}^{2}}+A{{D}^{2}}\] \[D{{B}^{2}}={{a}^{2}}+{{a}^{2}}\] \[\Rightarrow \] \[DB=a\sqrt{2}\] Area of square \[DBQP=a\sqrt{2}\times a\sqrt{2}=2{{a}^{2}}\] ? (2) From (1) and (2) Area of square: Area of square \[DBQP={{a}^{2}}:2{{a}^{2}}=1:2\]You need to login to perform this action.
You will be redirected in
3 sec