A) \[10\,\,{{m}^{2}}\]
B) \[11\,\,{{m}^{2}}\]
C) \[15\,\,{{m}^{2}}\]
D) \[19\,\,{{m}^{2}}\]
Correct Answer: B
Solution :
[b] Area of sector\[=\pi {{r}^{2}}\times \frac{\theta }{360}\] \[\therefore \] Area of sector OCBO\[\text{=}\pi \times {{8}^{2}}\times \frac{45}{360}=8\pi {{m}^{2}}\] Area of sector OADO\[\text{=}\pi \times {{6}^{2}}\times \frac{45}{360}=\frac{9\pi }{2}{{m}^{2}}\] \[\therefore \] Area of shaded region\[\text{=}\left( 8\pi -\frac{9\pi }{2} \right){{m}^{2}}\] \[=\frac{7\pi }{2}{{m}^{2}}=\frac{7\times 22}{2\times 7}{{m}^{2}}\] Area of shaded region \[=11\,{{m}^{2}}\]
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