A) 5 m
B) 8 m
C) 7.5 m
D) 9 m
Correct Answer: A
Solution :
[a] Let the width of path = x m \[\therefore \] \[(38-2x)(32-2x)=616\] \[1216-140x+4{{x}^{2}}=616\] \[4{{x}^{2}}-140x+600=0\] \[{{x}^{2}}-35x+150=0\] \[\therefore \] \[x=30,\] \[x=5\] Hence, the width of path = 5 mYou need to login to perform this action.
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