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SSC Sample Paper Mock Test-1 SSC CGL Tear-II Paper-1

  • question_answer
    If \[x+\frac{1}{2+\frac{4}{5\div 5+2}}=0,\]then the value of x is

    A)  \[\frac{3}{10}\]                        

    B)  \[\frac{-10}{3}\]

    C)  \[\frac{-3}{10}\]           

    D)  \[\frac{10}{3}\]

    Correct Answer: C

    Solution :

    \[x+\frac{1}{2+\frac{4}{5\div 5+2}}=0\] \[\Rightarrow \]\[x+\frac{1}{2+\frac{4}{1+2}}=0\] \[\Rightarrow \]\[x+\frac{1}{2+\frac{4}{3}}=0\]\[x+\frac{1}{\frac{10}{3}}=0\] \[\Rightarrow \]\[x+\frac{3}{10}=0\] \[\Rightarrow \]\[x=-\frac{3}{10}\]                      


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