A) 600
B) 500
C) 400
D) 300
Correct Answer: D
Solution :
If x % failed in Hindi and y% failed in English and z% failed in both. Then, the percentage of candidates who passed in both subjects \[=[(100-(x+y-z)]%\] \[=[100-(42+52-17)]%\] \[=[100-77]%=23%\] Number of candidates appeared \[=\frac{100\times 69}{23}=300\]You need to login to perform this action.
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