A) 5 days
B) 4 days
C) 9 days
D) 10 days
Correct Answer: D
Solution :
Number of days of his absence \[=\frac{Na-c}{a+b}\] [Here N = 30, a = 50, b = 5 and c = 950] Number of required days \[=\frac{30\times 50-950}{50+5}=\frac{550}{55}=10\]daysYou need to login to perform this action.
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