A) 100 K
B) 20 K
C) 400 K
D) 80 K
Correct Answer: A
Solution :
As, pressure (p) varies inversely as volume (V) \[\therefore \]\[p\propto \frac{1}{V}\]and \[T\propto V\]\[\Rightarrow \]\[p=\frac{{{K}_{1}}}{V}\]and \[T={{K}_{2}}V\] But \[V=50,\]\[T=25\]and\[p=1\] \[\Rightarrow \]\[{{K}_{1}}=50\]and\[{{K}_{2}}=\frac{1}{2}\]\[\therefore \]\[p=\frac{50}{V}\]and \[T=\frac{1}{2}V\] where \[V=200,\]then \[T=\frac{1}{2}\times 200=100\,\,K\]You need to login to perform this action.
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