A) 56%
B) 57.5%
C) 65%
D) 68%
Correct Answer: D
Solution :
Let length \[=100\,\,m\]and breadth \[=100\,\,m\] Area of square\[={{(100)}^{2}}=100000\,\,{{m}^{2}}\] New length \[=140\,\,m,\]New breadth\[=120\,\,m\] New area \[=(140\times 120)\,\,{{m}^{2}}=16800\,\,{{m}^{2}}\] Increase in area\[=16800-10000=6800\,\,{{m}^{2}}\] Increase percentage \[=\left( \frac{6800}{10000}\times 100 \right)%=68%\]You need to login to perform this action.
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