A) 70
B) 75
C) 73
D) 71
Correct Answer: C
Solution :
Total number of seats (Executive class) \[=500\times \frac{10}{100}=50\] \[\therefore \]Total number of seats (Chaircar) \[=500-50=450\] \[\therefore \]Total number of booked seats \[=500\times \frac{85}{100}=425\] Total number of booked seats (Executive class) \[=50\times \frac{96}{100}=48\] \[\therefore \]Total number of empty seats (Chaircar) \[=450-(425-48)=73\]You need to login to perform this action.
You will be redirected in
3 sec