A) 1
B) 2
C) 24
D) 25
Correct Answer: D
Solution :
We know that, if \[{{x}^{n}}+1\] is divisible by \[x+1\] when n is odd. In \[{{25}^{25}},\]25 is odd. \[\therefore \] \[({{25}^{25}}+1)\] is divisible by \[25+1\] or 26 \[\Rightarrow \] \[({{25}^{25}}+1-26)\] is divisible by 26 \[\Rightarrow \] \[({{25}^{25}}-25)\] is divisible by 26 \[\therefore \]When \[{{25}^{25}}\] is divided by 26 then remainder is 25.
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