A) \[14\frac{2}{7}\text{days}\]
B) \[33\frac{1}{3}\text{days}\]
C) \[18\frac{3}{4}\text{days}\]
D) 10 days
Correct Answer: D
Solution :
| 16 men = 20 women |
| 4 men = 5 women |
| Now, according to question, 16 men complete the work in 25 days. |
| \[\therefore \]1 man one day's work\[=\frac{1}{25\times 16}\] |
| \[\therefore \]4 men one day's work \[=\frac{4}{25\times 10}=\frac{1}{100}\] |
| Similarly, |
| 1 woman one day's work \[=\frac{1}{25\times 20}\] |
| \[\therefore \]5 women one day's work \[=\frac{5}{25\times 20}=\frac{1}{100}\] |
| \[\therefore \] 28 men \[=\frac{28}{4}\times 5=35\]women |
| \[\therefore \] 50 women one day's work \[=\frac{50}{25\times 20}=\frac{1}{10}\] |
| Therefore, 28 men and 15 women can complete the whole work in 10 days. |
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